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This text is meant to accompany class discussions. It is not everything there is to know about uniform circular motion. It is meant as a  prep for class. More detailed notes and examples are given in the class notes, presentations, and demonstrations (click here.)

Click for the questions that go with this reading
Velocity vs. Time

 

The velocity of the car on the the previous page is 1 m/s. The velocity is constant. At the start, (0 seconds,) the velocity is 1 m/s; at 1 s it is 1 m/s; at 2 seconds it is still 1 m/s; at 3 seconds it remains 1 m/s; at 4 seconds it is still 1 m/s and at 5 seconds it is also 1 m/s. A graph of the look like the one below.

Look at the slope on the previous graph of position vs time.

The slope on the position vs time graph equals the velocity.


Let's change the situation. Instead of the car traveling at a constant velocity suppose its velocity changes by 1 m/s every second. This is a constant acceleration of 1 m/s2. After 1 second, it would be traveling at 2 m/s; after 2 seconds, it would be traveling at 3 m/s; after 3 seconds it would be traveling at 4 m/s; at 4 seconds the velocity would be 5 m/s, and after 5 seconds it would be traveling at 6 m/s. The graph of the car's velocity would look like the one below.

More about acceleration on the next page.

quiz
1

If you were given a graph of velocity vs time, then how would you find the velocity at 5 seconds?

2

Find the velocity at 5 seconds for the velocity vs time graph shown at the right.

3

If you were given the graph of position vs time shown at the right, then how would you find the velocity at 5 seconds?

4

For the graph shown at the right, calculate the velocity at 5 seconds. (Hint: The slope is the same at every second along a straight line.)

5

For the graph shown at the right, describe what you need to do to find the velocity at 5 seconds.

6

For the graph shown at the right, calculate the velocity at 5 seconds.

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by Tony Wayne ...(If you are a teacher, please feel free to use these resources in your teaching.)