When accounting for the amount of humidity in the air, the breakdown voltage of air is between 20,000 and 70,000 V/inch. On a clear, dry, day in the winter time, it is not unusual for the air's breakdown voltage to be 50,000 V/inch. If you rub the fur of a pet and then as you touch a door knob get an spark of between your hand and the door knob that is 1/2 an inch long, then what is the potential difference between the two ends of the arc of electricity?
When accounting for the amount of humidity in the air, the breakdown voltage of air is between 20,000 and 70,000 V/inch. On a clear, dry, day in the winter time, it is not unusual for the air's breakdown voltage to be 50,000 V/inch. If you rub the fur of a pet and then as you touch a door knob get an spark of between your hand and the door knob that is 1/2 an inch long, then what is the potential difference between the two ends of the arc of electricity?
This question is solved using the breakdown voltage and dimensional analysis.
Givens
Vbreakdown =50,000V/in
d = 0.5 inches
![The answer is 25,000 Volts](pics/ExampleBreakdown_V_Solution.gif)